[Wranglers] Snowflake now supports Higher-order Functions (Lambda Expressions)

[Ali, Saqib]

Using Lambda expressions and TRANSFORM function to extract values from a
JSON array

https://qosf.com/using-transform-function-in-snowflake-to-extract-values-from-a-json-array.html



On Tue, May 14, 2024 at 2:48 PM Ali, Saqib <docbook.xml at gmail.com> wrote:

> A nice blogpost by Kala Govindarajan on using Higher-order Functions,
> FILTER and TRANSFORM, in Snowflake:
>
> https://medium.com/@kala.govindarajan/unlocking-efficiency-with-semi-structured-data-leveraging-snowflakes-higher-order-functions-ed89b51801a0
>
>
> Saqib
>
>
>
> On Fri, May 10, 2024 at 8:53 AM Ali, Saqib <docbook.xml at gmail.com> wrote:
>
>> Snowflake just announced support for  Higher-order Functions (Lambda
>> Expressions). See the following blogpost by Qinyi Ding:
>>
>> https://medium.com/snowflake/snowflake-supports-higher-order-functions-dfa4b7682f7a
>>
>> Saqib
>>
>
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